Question

For the following reaction, 3.94 grams of nitrogen gas are mixed with excess oxygen gas. The reaction yields 7.55 grams of nitrogen monoxide. nitrogen (g) + oxygen ( nitrogen monoxide (g) What is the theoretical yield of nitrogen monoxide ? What is the percent yield for this reaction ? grams Submit Answer Try Another Version 2 Item attempts remaining

Answer 1

dus al moles of N2 = ass = 394 Molar mads 949 = 0.141 nol MAALAAAAAAAAAAA012120000 Solution Ron of Na and O₂ N2 (8) + O₂(g) 200 (9) applied POAC rule. moles of No moles of N2 cofficient cofficient moles of No – 0.141 mal 2 1 moles of No = 0.282 mol Steho ford thewritteal mass of No. Mads of NO = molave mashed X males = 30.01 g/mol x 0.282 mal = 8.45 g Step I find 7 yeuld. % Yeld = actual meds x 100 the writical mat = 7.55 g x 100 = 89.4% 8.450 Thank you, May it help you can