Question

At 25C, the vapor pressure of pure benzene is 0.1252 atm. When 6.50 g of a sold sample of naphthalene,C10H8(128.17 g/mol), is dissolved in 76.0 g of pure benzene, C6H6, calculate the vapor pressure of benzene above the solution

oy looL 2. Raoult's Law. At 25 °C, the vapor pressure of pure benzene is 0.1252 atm. When 6.50 g of a solid sample of naphthalene, C10Hg (128.17 g/mol), is dissolved in 76.0 g of pure benzene, C6H6 (78.0 g/mol), calculate the vapor pressure of benzene above the solution. [0.119 atm] 2 Shatm

Answer 1

Relative lowering of vapour pressure Apl -pi-pi -=x2 mole fraction of solente Relative lowering of vapour pressure pio-bi since the = 2 nit na P nitna solute Here n, and nu are the no. of moles of solvent and respectively. For dilute solution nz<en, hence neglecting na in the denominator pi-pl - na bi-vapour pressure pure solvent of Robi - Wex M - M2 wi the Here w, and we molar masses of are the solvent masses and Mr and Me are and solente respectively 0.1252-bi - 6.50 128.17 78.0 76-0 0.1252 Tbi = 0.119 atm