Question

* Question Completion Status Svante Antonlus, a Swedish scientist, detined the behavior of acids and bases in aqueous solution in terms of reactions Invang hydrogen Ions (aka protons, H). According to the Arrhenius definition an acld will lontze by donating a hydrogen lon to a base (E) to form its conjugate bose (A) The Arrhenius definition states that a base (B) willonize by accepting a proton from an acidHA to form its conjugate acid (BH) The general form of this reactions: Ha) Bledi = BH lal A'la) For the following reaction identify the acid and base reactants and the conjugate add and conjugate base products: H2H 30 zlac) + NH324) = (2-302741NH4lag) HC2H307691 A conjugate add Nil and C2H302 (1) C base NH ) D.conjugate base 1 points For any general acid (HA) i innirarion reaction in water is Haq) + H 200)= H 30 (aq) + ATC The Ionization reaction equilibrium constant is given the special name the acid ionization constant Rg. Fortunately the format for the acid ionization constant expression is identical to thet for any other equilibrium constant expression K-M0341 na [HA For any general base (0) its ionization reaction in water is B/32 + H2011) - BH (39+ OH T4 Where should the concentration of each species in the general base lonization rosetion appear in the base ionization constant o expression? A numerato 201 B. neither the numerator nor denominator . - AH1 OH C. both the numerator and denominator D. denominator

Answer 1

A)

The acid-base reaction is as follows:

HC₂H₃O₂(aq) + NH₃(aq) $\rightleftharpoons$ C₂H₃O₂^-(aq) + NH₄⁺(aq)

Here,

Acetic acid(HC₂H₃O₂) is acid.

Ammonia(NH₃) is Base.

Acid donates a proton to base an becomes a conjugate base of acid.

Thus, Acetic acid donates a proton and became a conjugate base C₂H₃O₂^-(aq).

The base accepts a proton from acid an becomes a conjugate acid.

Thus, ammonia accepts a proton from acetic acid and became a conjugate acid NH₄⁺(aq).

Thus,

HC2H3O2(aq)	Acid
NH3(aq)	Base
C2H3O2-(aq)	Conjugate base
NH4+(aq)	Conjugate acid

(B)

The general base ionization reaction in water is as follows:

B(aq) + H₂O(l) $\rightleftharpoons$ BH⁺(aq) + OH^-(aq)

Thus, the base ionization constant expression is as follows:

K_b = [BH⁺][OH^-] / [B] ----------Since H₂O(l) is pure liquid, neglect the [H₂O]

Thus,

[B]	Denominator
[H2O]	Neither the numerator nor the denominator
[BH+]	Numerator
[OH-]	Numerator