Question

Work and Energy Homework 2 1.) A spring with constant 300 N/m is 0) to be 8 cm longer. a.) How much work is done to the spring while stretching? b.) It the spring is stretched twice as far, how much work will be done? c) Is the work in the spring stored, or must the energy immediately change onm?

Answer 1

K = 300 N/m, x = 8 cm = 8 times 10^-2 m Work done = stored potential Energy = 1/2 kx^2 = 1/2 times 300 times (8 times 10^-2)^2 = 0.96 J of x = 16 cm = 0.16 m Work done = 1/2 kx^2 = 1/2 times 300 times (0.16)^2 = 3.84 J Yes as soon as work done upon the spring, it will get stored as potential energy of spring