Question

12. + -11 points KatzPSEf1 13.P.053.MI. My Notes + Ask Your Teacher Two children (m = 32.0 kg each) stand opposite each other on the edge of a merry-go-round. The merry-go-round, which has a mass of 1.76 x 102 kg and a radius of 1.6 m, is spinning at a constant rate of 0.38 rev/s. Treat the two children and the merry-go-round as a system. (a) Calculate the angular momentum of the system, treating each child as a particle. (Give the magnitude.) kg · m²/s (b) Calculate the total kinetic energy of the system. (c) Both children walk half the distance toward the center of the merry-go-round. Calculate the final angular speed of the system. rad/s Need Help? Master It Submit Answer

Answer 1

I m= Bakg M=1076x10² = 176 kg R= 10fm . W = 0.38 souls = 0-38 x 29 madis w = 2.387 Is MR? + 2x mx R2. I - 2x196x9•6)2+ 2x32x0.632 = 225.28 +163.84 I = 389.12 kg.m? a) L= I w = 389.12 x 2.387 T2 = 928.83 kg. mays x 3 + 2 x (2.38+) | by kẻ : 33 19 = TKE = 1108.56J

c7 new R=0.8m. I - 225.28 + 40.96 I= 266:24 Kg.ma. I, W, = Iz wz W = 389.12 x 9.387 266-24 I w2=804 i rad s