Question

Consider the reaction of HClO₄ with P₄O₁₀ to form H₃PO₄ and Cl₂O₇. If 5.51 g P₄O₁₀ is reacted with excess HClO₄ and 6.70 g of H₃PO₄ is ultimately isolated, what is the percent yield for the reaction?

Answer 1

12HClO4 + P4O10 ------------> 4H3PO4 + 6Cl2O7

according to balanced reaction

283.89 g P4O10 gives 4 x 98 g H3PO4

5.51 g P4O10 gives 5.51 x 4 x 98 / 283.89 = 7.61 g H3PO4

theoretical yield = 7.61 g

actual yield = 6.70 g

% yield = (actual yield / theoretical yield) x 100

% yield = (6.70 / 7.61) x 100

% yield = 89.8 %