A 90% confidence interval for p is given as (0.37,0.63). How large was the sample used...
A 95% confidence interval for p is given as (0.27,0.53). How large was the sample used to construct this interval? n(Round up to the nearest observation.)
A 95% confidence interval for p is given as (0.19,0.41). How large was the sample used to construct this interval? (Round up to the nearest observation.)
The following is a 90% confidence interval for p:(0.26, 0.54). How large was the sample used to construct this interval?
5. The following is a 90% confidence interval for p:(0.26, 0.54). How large was the sample used to construct this interval? (10%) 6. If you wish to estimate a population mean to within 0.2 using a 95% confidence interval and you know from prior sampling that q? is approximately equal to 5.4, how many observations would you have to include in your sample? (10%)
Determine the sample size n needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and the margin of error equals 7%. n= (Round up to the nearest integer.)
a) Find n for a 90% confidence interval for p with bound on the error of estimation (margin of error) = 0.038 using an estimate of p = 0.7. (Round up to the nearest whole number.) NOTE: If you have the 98% or the 99% confidence interval for this question, PLEASE READ THE INSTRUCTIONS at the top of the assignment. b) Find the conservatively large value for n using the same confidence interval and bound on the error of estimation...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal palces Of 98 adults selected random from one town, 68 have health insurance Find a 90% confidence interval adults in he own who have heal e proportion on r e a ns rance 0585 < p < 0 802 B. 0.617<p<0.770 A. C. 0603 p<0.785 D. 0.574p<0.814
Use the given degree of confidence and sample data to...
Use the given degree of confidence and sample data to construct a confidence interval for the population mean u. Round to the nearest tenth, if necessary n = 25, = 80, s = 10, 99% confidence 81.1 < p < 88.4 74.4 < p < 85.6 79<< 89 80 < p < 88
The formula used to compute a large-sample confidence interval for p is p̂ ± (z critical value) p̂(1 − p̂) n What is the appropriate z critical value for each of the following confidence levels? (Round your answers to two decimal places.) a) 85%
The formula used to compute a large-sample confidence interval for p is p̂ ± (z critical value) p̂(1 − p̂) n What is the appropriate z critical value for each of the following confidence levels? (Round your answers to two decimal places.) 87%