Question

Iglance the following equations – NH₃ +_ 02 +_ CHU - HON+ BH2O - KNO3 + _ H₂CO3 → _K.CO₂" _HNO3 - H202 → _H2 +_ Oa BE3 + _Lig 50g --. _B,(50,+_LiF - Beg C + H2O → _ Belota + - Chil - Chun -02 -.CO2 + _Had... Caz (PO )2 + - Hasou _ CaSO4 * _ Ca(Ho Paula FegO + _C → _CO2. - _ Fe.. Al + - Os - Ha – NHUF + AICI, —_, C1 _AIF, - HCl + _NaOH NaCl + Hao -No Hp - - VHS IT I 1 1 1 1

please help balance these equations and write step by step introduction so I can understand the process. thanks

Answer 1

NH3 + O2 + CH4 -----> HCN + H2O

This is not balanced equation. If we multiply NH3 by 2 then

2NH3 + O2 + CH4 ----> 2HCN + H2O

To balance carbon both sides

2NH3 + O2 + 2CH4 ---> 2HCN+ H2O

To balance O & H both sides

2NH3 + 3O2 + 2CH4 ----> 2HCN + 6H2O

(2) KNO3 + H2CO3 ----> K2CO3 + HNO3

This is not balanced equation. If we multiply KNO3 by 2 then

2KNO3 + H2CO3 ----> K2CO3 + HNO3

Nitrogen is not balanced so balance nitrogen

2KNO3 + H2CO3 ----> K2CO3 + 2HNO3

(3) H2O2 ----> H2 + O2

This is balanced equation

(4) BF3 + Li2SO3 -----> B2(SO3)3 + LiF

This is not balanced equation. If we multiply BF3 by 2 and LI2SO3 by 3 then

2BF3 +3 LI2SO3 -----> B2(SO3)3 + LiF

Balance rest of the things

2BF3 + 3Li2SO3 ----> B2(SO3)3 + 6 LiF