Question

C 2.40 g of NH4Cl in 930.0 mL of solution MAH, Mc- = d 2.40 g of K3PO4 in 930.0 mL of solution Mk+ = Mpo,3 =
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Answer #1

Molarity = no. of mules of Solute Volume of solution (in L) no. of moles = mass M.W. (C MW of MHyll = 53.491 g/mol .. no. of

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