Homework Answers
Balanced equation:
3 Zn + 2 H3PO4 ====>
Zn3(PO4)2 + 3
H2
Reaction type: single replacement
Mass of Zinc = 10. 8 gm
Moles of Zinc = 10.8 g /65.38 g/mol = 0.165188 Moles
Volume of phosphoric acid = 23.6 ml
Concentration of phosphoric acid = 0.555 M
Moles of phosphoric acid = 23.6 ml x 0.555 /1000 = 0.013098 Moles
Limiting reagent is H3PO4.
Moles of H2 produced = 0.01964700 Moles
The molar volume of gas at STP is 22.4 liters per mole.
Volume of H2 produced = 22.4 Liter / mole x 0.01964700 mole = 0.44 Liter or 440 ml
440 ml of H2 will be produced.
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