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Check my work Enter your answer in the provided box. A 221 g aluminum engine part at an initial temperature of 15.14°C absorb
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heat (Trind-Tinitial) specific heat = massx 75x1035=221 gx 0.900 I x C I final -15142) Itinal - 15.14°C = 317.01°C 377.01+ 15

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