Question

please answer 38, thanks.

26. Given a test statistic of 2.09 paired with a crtical z-score of 2 33 on a one tailed test, then the conclusion fail to reject H. at α-1% b)fail to reject H,at α-5%e reject KedacceptH,ata-1% d) reject, and accept H. at a " 5% At a 95% a) e) nooc of these 27. interval, how often would we expect u to 5% 95% c)1% fall outside the inerval estimate? 28. We are allowed to use the normal distribution if d)90% e) 10% ơ is known b) n 500 more a b) df e) the "test statistic" (t.s) increase the contidence level nb) increase the sample size )incresase the cridical region or more o) either () or(b) ) both (a) and (b) e) noe of these 29. When we determine a is test, it's compared to what value to make our decision? 30. action will cause the confidence interval to widen? d) increase a e) all of these except choice (a) 31. If I joey is chosen at random, what's the probability that it weighs between 450 and 470 mg 32. If 1 joey is chosen at random, what's the probubility that it weishs exactly 500 mg? 33. If 10 joeys are chasen at random, how likely is it that they average between 450 and 470 m? b) . 121 ) 2266 d) 1056 e) none of these b) .121 2266 1056 none of these b) less than 1% c) 5% d) 0% e) none of these a)196 34. What is the critical value (zs or te) to be used in this test? d) 2.12 e) none ofthese ±1.645 c) ±2.13 a) +1.96 e)none ofthese d) .0456 What is the p-value result for this test? c).0228 35. b).0250 a).0050 Does Christine reject or fail to reject (FTR) Ho and for what reason? reject because p-value <a cFTR because p-valse sa 36. 82 FTR because is reject because Its| <闷넉 reject because p-value> α 37. What is the new critical value (ze or ts) to be used in this test? b) 1.645 c) +2.13 d) 2.12 e) none of these a) 1.96

Answer 1