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You are conducting a test of homogeneity for the claim that two different populations have the...

You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data.

Category Population
#1		 Population
#2
A 25 47
B 44 80



What is the chi-square test-statistic for this data?
χ2=χ2= Incorrect

math   Statistics-And-Probability   
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Answer Date: 19/01/2019 Test the claim that the two different populations have the different proportions at 5% level of significance. The null and alternative hypothesis is, The null hypothesis is that the two different populations have the same proportions. The alternative hypothesis is that the two different populations have the different proportions. The chi-square test-statistics ofhomogeneity is, By using MINITAB software, find chi-square test statistics with help of following steps: 1)Import the data 2) Select Contingency table fom Chi-Square in MegasStxt option from Add-Ins 3) Select Chi-Square and Expected frequencies in Output options menu. 4) Click Ok.Chi-square Contingency Table Test for Independence Population 1 Population 2 47 46.65 80 80.35 127 127.00 Total 72 72.00 124 124.00 196 196.00 25 25.35 Categpry A Observed Expected Category B Observed Expected Observed Expected 43.65 69 69.00 Total 012 chi-square 1 df 9143 p-value From the Excel output, the chi-square test-statistics of homogeneity is 0.012 The p-value is, From the Excel output, the chi-square testp-value is 0.9143. The p-value is l0.9143Decision The conclusion is that the significant p-value is higher than 0.05 which is 0.9143, so the null hypothesis is not rejected at 5% level of significance. There is insufficient evidence to indicate that the two different populations have the different proportions. The result is not statistically significant.

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