Question

Ka of HNO2 is 4.0*10^-4

Can you work out 42 and 44 for me. Along with explanation.

42. What volumes of 0.50 M HNO, and 0.50 M NaNO, must be mixed to prepare 1.00 L of a solution buffered at pH = 3.55?! 43. Consider a solution that contains both CsHSN and CsH5NHNO3. Calculate the ratio [CSH N]/[CsH NH+] if the solution has the following pH values: a. pH = 4.50 2101 c. pH = 5.23 olo lo dorato b. pH = 5.00 d. pH = 5.50 44. Calculate the ratio [NH]/[NH4+] in ammonia/ammonium chloride buffered solutions with the following pH values: a. pH = 9.00zed c. pH = 10.00 | b. pH = 8.80 d. pH = 9.60

Answer 1

42. pH = pka & log [NaNO2] 1 [HNO2] A e ka for HNO2 = 4x10-4 pka = - log (4x10-4) pka = 3.40 pH = 3.40 + log [NaNO2] * “ (HN 0,7 I.8 3.55 – 3.4 = log [NaNO2] Sony CHINO 2] NaNO2] I 1.41 SA xos x (HNO2). - a -928NSS abfr [NaNO2] = 1.41 [HNO2] Given [NaNO2] + [HNO2] = 1 1.41 [HNO2] + [HNO2] = 1 VHNO2 = 0.415 L IN NaNO₃ = 0.585 L