A) Amplitude of oscillation
A = mg/k
=0.5×9.8/350= 0.014 m
= 1.4 cm.
Therefore equilibrium position lies 1.4 cm below the initial position.
Block will further move 1.4 cm below the equilibrium position before coming to momentary rest.
Distance moved from initial position = 2A = 2.8 cm
(B)
= 0.37 m/s
(C)
= 0.24 s
A spring with spring constant 350 N/m hangs from the ceiling. James Bond attaches a block...
A spring with spring constant 350 N/m hangs from the ceiling.
James Bond attaches a block of mass 0.7 kg to the unstretched
spring and releases it from rest.
(Part A) How far below the starting point does the block fall
before coming momentarily to rest? Answer in cm
A spring with spring constant 350 N/m hangs from the ceiling. James Bond attaches a block of mass 0.7 kg to the unstretched spring and releases Part A it from rest....
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