Question

1. What is the crystal field stabilisation energy (CFSE) of a d5 metal ion in an...

1. What is the crystal field stabilisation energy (CFSE) of a d5 metal ion in an octahedral ligand field surrounded by weak field ligands?

+5Dq

-20Dq

0Dq

-5Dq

-20Dq + P

2.

The relative ordering of the d orbital energy levels for a complex such as [Cu(H2O)6]2+ which exhibits tetragonal elongation due to the Jahn-Teller Effect is:

Group of answer choices

xz = yz = xy < x2-y2 = z2

xy < xz = yz < x2-y2 < z2

xz = yz < xy < z2 < x2-y2

xz = yz < xy < x2-y2 < z2

xz < yz < xy < x2-y2 < z2

3. Place the following complexes in order of their increasing rate of substitution by H2O: [Ir(NH2)6]3+, [V(H2O)6]3+, [Cr(H2O)6]3+.

Group of answer choices

[Cr(H2O)6]3+  < [V(H2O)6]3+ < [Ir(NH3)6]3+

[Ir(NH3)6]3+ < [V(H2O)6]3+ < [Cr(H2O)6]3+

[Ir(NH3)6]3+ = [V(H2O)6]3+ =[Cr(H2O)6]3+

[V(H2O)6]3+ <[Ir(NH3)6]3+ < [Cr(H2O)6]3+

[Ir(NH3)6]3+ < [Cr(H2O)6]3+ < [V(H2O)6]3+

0 0
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Answer #1

1.

Correct option: 0 Dq

The gap between t2g and eg orbital is low for an octahedral complex with weak field ligand. The complex will thus be a high spin complex in order to avoid the unfavorable spin pairing energy. Hence, in octahedral field of d5 configuration, 3 d electrons will be in low energy t2g orbital and 2 d-electrons will be in high energy eg orbital.

The stabilization energy due to 3 electrons in t2g = 3 x (-4 Dq) = -12 Dq

The destabilization energy due to 2 electrons in eg = 2 x (+6 Dq) = 12 Dq

Therefore,

CFSE = - 12 Dq + 12 Dq

           = 0 Dq

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