Question

1 Keview | Constants 1 Periodic Table Spell out the full name of the compound. Submit Request Answer Part B Spell out the full name of the compound.

Answer 1

3, 1 6 5-methyloct-2-yne (or) 5-methyl-2-octyne 5-ethyl-4-methylhept-1-yne 2-bromooct-4-yne (or) 2-bromo-4-octyne "e" gets priority over "m" hence ethyl comes first name.

The IUPAC name of the any compound contains 3 parts prefix+ rootword + suffix Prefix = any substitutents rootword = longest chain containing most number of carbons if the chain contains 1 carbon = meth 2 carbon = eth 3 carbon = prop 7 carbon = hept 4 carbon = but 8 carbon = oct 5 carbon = pent 9 carbon = non 6 carbon = hex and so on Suffix = if the compound contains single bond (C-C) only then suffix 'ane double bonds (C=C) 'ene triple bonds 'yne For selecting prefix numbering, the substituents numbers has to be given in such way that the sum of the all substituents should be as less as possible. For selecting rootword chain, the chain with more number of carbons has to be selected In all the given compounds alkanes are present, hence the suffix is 'ane' in all the four compound For all the compounds, blue coloured part of the name is prefix. red coloured part of the name is rootword and pink coloured part of the name is suffix