Question

The circuit shown has the following values for voltages and resistors: V1 13.0 V V2-12.0 V R1 5.65 Ohms R2-1.61 Ohms R3 4.82
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Answer #1

Using KVL in two loops,

V1 - R3*I3 - (R1+R2)*i1 = 0 or 13-4.82i3 - 5.65i1 - 1.61i1 = 0

V2 - R5*i2 - R4*i2 - R3*i3 = 0 or 12 - 5.05*i2 - 4.62i2 - 4.82i3 = 0

and by KCL, i1+i2-i3 = 0

solving the three equations and three unknowns, i2 = 0.54 , i3= 1.40 and i1= 0.86

i1 = 0.86 A answer

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