Question

Physics II Do Not Write on This Question Sheet! Lab Quiz 17. Calculate an electric field at the point 0.59 m away from a charge Q+9.7uC. (A) 251 쁘 (B) 148쁨 (C) 279e-5쁨 (C) 2.79e-S (D) 325뜯 kN (E) 4.35 / 18, what is the direction of the electric field in #177 (A) Towards the charge (B) Away from the charge (C) An electric field has no direction 19. From the sketch of the field lines shown in Figure 1, determine the ratio QA (including the sign) QB Figure 1: Electric Field lines of a pair of charges Qa and QB 13 D) 18 18 18 13 (A) (E) 13 20. Determine the signs of each of the three charges shown in Figure 2: (A) All three charges are positive. (B) All three charges are negative. (C) A is negative, while B and C are positive. (D) A is positive, while B and C are negative. (E) A and B are positive, while C is negative. Figure 2: Electric Field lines of three charge

Help!

Answer 1

17)

Electric field, E = kq/r^2 = (9 x 10^9)(9.7 x 10^-6)/(0.59^2)

E = 251 kN/C

18)

B) Away from the charge

19)

Qa = positive charge ( electric field outward)

Qb = negative charge (electric field inward)

Qa < Qa, because electric field lines are denser near Qb than Qa.

So ratio must be = Qa/Qb = - 13/18

======

A = positive charge

B = negative charge

C = negative charge

Comment in case any doubt please rate my answer ...