Question

can someone help me on this I dont understand

Calculate the DU for C,HBrO Solution Br counts as an H and O can be ignored, so calculate as though the formula CH DU-(2x8)+ 2-14] 2 PROBLEM 2.9 Calculate the DU for these formulas and draw two constitutional isomers for each a) CHO d) CH,CIN b) C H,N e) C HINO c) CHiF Due ne PROBLEM 2.10 Determine the DU for each of these structures OCH,CH, b) N

Answer 1

DU stands for degree of unsaturation. Degree of unsaturation for the given - organic compound represents the number of multiple bonds of number of rings. present in it. an the given compound can be calculated as DU e 10 no of x DO = (no. of carbons + 1)- no. of H's & no. of nitrogen atom where x - halogen atoms DU = (Cat1) - H - X n + No 9 H 3 Bro no. of carbons = 8. no. of Hydrogens = 13 no of halogen atoms = 1 (Br) substitute in 0 , to get Du DU = (8+1) - 13 - 12 - 9-7 = 2 Hence, the given compound has a ring & a double bond.

the given compound has a triple bono two the compound has double bonds. given The given compound may contain two rings. DU can be easily understand that the given compound contain how many hydrogens are less than the parent Satugated hydrocarbon For example :- G H 3 Bro. The hydrocarbon (alkane) with should have (stant2 & 9418) 18 Hydrogens. But the given compound has 13 Hydrogens and one(B) halogen atom whose valency is same as hydrogen. So total 14. 18-14 = 4 Hydrogen atoms are less than

the alkane octane. le, two pairs of hydrogens are less This represent the given compound may contain either two double bonds or a triple bond of a double bond or a ring of two rings problem 2.9 a) GoHo DU (Cnt) - Hn -Xn + NA DU OH - 11-10 DU - 1 The given compound contain a double bond or a ning C = N 6) CHON DU = (C+1) - H - Xn + - (6+1) - + = - 7-4 – 3

c) CHF DU = (n + 1) - H - X n + No = (1+1) - 14 - 2 = 8 - 16 28-8 m r ЕЕ - 0 Duo 2) d CH CIN DU = (C+1) - Ho - Xn & No .. = (6+1) - 8 - 1 +A - 7-4 ) HNA CH3 DU=3 e) Cat S No - DO = (9+1) - 15 + 1 - 10- - 10-7 = 3 Na C CH₂ 'CH3

Problem 2.10 a) F COCH CH3 OCH, ette Benzene ring has 3 double bonds & Dhe ging. So total Du for CH = 4 6 6 .c- bond has a double bond Hence, for the giren compound has DU = 4+1 = 5 T 1 triple bond in CEN which has Dug & bond has DU = 1 - c=c- has DU = 1 Total DU = 2+1+1 = 4