Question

Can i get a brief summary of hoe to answer number 1 and 2

a hyper 1. Determine the osmolarity of each of these solutions. Circle any hypertonic solutions. (Cellular fluids have a concentration around 0.28 M). Visoton a. 15.3 grams of sodium chloride in 325 mL of solution. b. 31.6 grams of lithium nitrate in 742 mL of solution. C. 5.3% (m/v) solution of calcium bromide in water. d. 0.085 M sodium sulfate a. Circle the solution with the higher osmotic pressure. 0.33 M calcium chloride 0.45 M lithium bromide b. Circle the solution with the higher vapor pressure. 0.33 M benzene (CH) 0.66 M toluene (CH) c. Circle the solution with lower freezing point. mere to search

Answer 1

CA Sounds osinolarity - 12 C Molasity xn) no coetlicant of Lössociation osmolarity & Molarity an x 1000 molarity & Weight x - More inlay laleight Vinmo MO) 15.3 gram Nach in 325ml Solution Naul Wel = 15.3. Nach moliut = 58.und V: 325mi " M: 15:34 x 1000 1 ss uyg 325 M = 0.805.m. [Nace - Natteł osmolarity of slael = 0.803 82 ne2 1.61 b) 31.6g of Li (Nos) in 742m Linos W+= 31.69 moleut= 68.9469 v= 742 M01

M= 31.6g x 1000 689462 742 mol c) M= 0.6177 LiNos > Lit +Nos nor Osmolarity = 0.61742 = 10235M 5.3"). M/ solution of cable in inlates. S3-). лекм 5.30g Cabry.in loomi inlaty, Cabra. Wt = 530g . Molenta 189.83% Ve loomu Ma 4.30 x 1000 Too, Tog ogg Ma 0.265. Cabra & cat2 +255 mas osmolarity = 0.265 X3 C 0 9795

d) 0.08sm sodium sulfate (Nassow) Nazsou znat et son 2 na3 Osmolarity = 0.08583 = 0.255. | 2) a) osmatic Pressure (TV) 2 in molarity. na dissociation constant. M= molarity. 0.3341 CaCl2 0usm Libri cache -> catatach .. Libr> Litter ne -- nas. 0:33 X3= ongg. =orgo Auswas cacha). 0.45X2 b) Highes Vapous Pressure 1 0.33 Benzene (Cats)