Question
1. Given n=2500 and p=0.86, find the margin of error E that corresponds to a 99% confidence level

2. you are given a margin of error as three percentage points in a confidence level of 99%. If the same percentage from arecent poll is 35%, find the minimum sample size to estimate a population proportion.

corresponds to a 99% confidence (1 point) 1. Given n level. 2500 and β-086, find the margin of error E that 0.014 0.048 0.018 0 0.007 (1 pont 2. You are given a margin of error as 3 percentage points and a confidence level of 99%. If the sample percentage tom a recent poll is 35%, find the minimum sample size to estimate a population proportion. O 496 2579 O 1677 0 248
0 0
Add a comment Improve this question Transcribed image text
Answer #1

1)Margin of error E= z × sqrt( p (1-p)/n )

We have given population proportion and sample values let find z value from z table in 2 tail at 99% confidence.

2) sample n= (Z/E)^2 (p' (1-p'))

Given E and p values and find z value from z table at 99% confidence in 2 tail.

And always round the sample value to the next highest value

り Gwen Sample ,Y) 2500. f: population propooHon ะ 0.86 n. Yom 2- tablo 525086(o.u) 2.500 2.545 (0.00674) 2) Sample proportion

Add a comment
Know the answer?
Add Answer to:
1. Given n=2500 and p=0.86, find the margin of error E that corresponds to a 99%...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (ipom) 1. Given n-2500 and β 0.86, find the margin of error E that corresponds to...

    (ipom) 1. Given n-2500 and β 0.86, find the margin of error E that corresponds to a 99% confidence level o 0.014 0 0.048 0 0.018 0.007 2. You are given a margin of error as 3 percentage points and a confidence level of 99%. Ifthe sample percentage from a recent poll is 35%, find the minimum sample size to estimate a (1 point) population proportion. 496 e 2579 1677 248

  • you are given a margin of error as 3 percentage points and a confidence level of...

    you are given a margin of error as 3 percentage points and a confidence level of 99%. if the sample percentage from a recent poll is 35% find the minimum sample size to estimate a population proportion. 496 1677 248 2579

  • Assume that a sample is used to estimate a population proportion p. Find the margin of...

    Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. In a clinical test with 1600 subjects, 800 showed improvement from the treatment. Find the margin of error for the 99% confidence interval used to estimate the population proportion. a. 0.0322 b. 0.0184 c. 0.0245 d. 0.0282 ON

  • Assume that a sample is used to estimate a population proportion p. Find the margin of...

    Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 384 with 87% successes at a confidence level of 99.5%. M.E. = % Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round final answer to one decimal place A political candidate has asked you to conduct a poll to determine what percentage of people...

  • Assume that a sample is used to estimate a population proportion p. Find the margin of...

    Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 370, x = 59 Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places....

  • Assume that a sample is used to estimate a population proportion p. Find the margin of...

    Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 259 with 74.9% successes at a confidence level of 99%. M.E. = % Report answer accurate to one decimal place (as a number of percentage points). Answer should be obtained without any preliminary rounding (however, the critical value may be rounded to 3 decimal places).

  • given n = 875 and p = 0.45 find the margin of error E that corresponds...

    given n = 875 and p = 0.45 find the margin of error E that corresponds to a 95% confidence level. .001 .033 .044 .016

  • Assume that a sample size is used to estimate a population proportion p. Find the margin...

    Assume that a sample size is used to estimate a population proportion p. Find the margin of error E that corresponds to the following statistics and confidence level. Round the margin of error to 4 decimal places. 95% confidence, n = 9000, of which 35% are successes. Use a TI84 and show all of your work

  • Determine the margin of error for a 99​% confidence interval to estimate the population proportion with...

    Determine the margin of error for a 99​% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 for the following sample sizes. a. nequals100             b. nequals180             c. nequals260 LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table. a. The margin of error for a 99​% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 and sample size nequals100 is nothing.

  • Assume that a sample is used to estimate a population proportion p. Find the margin of...

    Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. bing bing ocene 99% confidence; n = 5900, x = 1770 000 a. 0.00878 b. 0.0117 c. 0.0135 d. 0.0154

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT