For the following reaction, 0.118 moles of ammonia are mixed with 0.457 moles of oxygen gas.
For the following reaction, 0.118 moles of ammonia are mixed with 0.457 moles of oxygen gas.
ammonia(g) + oxygen(g) → nitrogen monoxide(g) + water(g)
What is the formula for the limiting reagent?
What is the maximum amount of nitrogen monoxide that can be produced?
Homework Answers
a) ammonia is the limiting reagent
b) 0.118 mole of Nitrogen monoxide will be formed.
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For the following reaction, 0.118 moles of ammonia are mixed with 0.457 moles of oxygen gas.
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