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-CH₂- VIII. BONUS. A molecule with the formula C6H10 has three singlets at 0 14 (6H), 2.45 (1H), and 3.3 (3H). The IR shows t
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CH3 Hc=c- cno-CH3 & Hoo HNonR DU= 2 (6)+2 -10 an 33, b- 2.45 (-1.40 singlet, 3 H singlet, IH singlet, 6H - 2

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