Question

explain in detail, please.

A23. What is the expression you would develop to calculate the molar solubility, s, of Ca(OH)2 in a 0.2 M CaCl2 solution? (A) 0.45 + 282 (B) 483 (C) 0.452 + 253 (D) 0.852 + 453 (E) 0.252 + s3 A24. A chemist separately measures out 3 x 10-4 mol calcium chloride, 3 x 10-4 mol magnesium chloride and 1.8 x 10-3 mol sodium hydroxide and dissolves each one of these in a volume of 100 mL of water. They then mix the three separate solutions together to form a single solution. The solubility product for calcium hydroxide (Ca(OH)2) is Ksp = 5.02 x 10-6 and for magnesium hydroxide (Mg(OH)2) is Ksp = 1.8 x 10-9. Based on these Ksp values, determine which of the following will occur? (A) (B) (C) (D) (E) Both calcium hydroxide and magnesium hydroxide will form a precipitate. No solid forms. A precipitate of magnesium hydroxide forms. A precipitate of calcium hydroxide forms. Initially a precipitate of magnesium hydroxide forms, however, upon standing, it is transformed to calcium hydroxide.

Answer 1

A 23 we have to develope an expression to calculate the molar Solubility s of calor)z in a 0. 2M Cache Solution. We know that cacla dissociate as Follocos: cacle = cazt tact 0. 2M 280. 2m = 0.4M

Since molarity of cacle is 0.2M so molarity of cat con = 0.2M molarity of .ce tons = 2x0.2M=0.4m we know that Molay solubility of cons of Calot) in cachee (0.2 M) Solution is 's. In cache Solution 0. 2M caut con is already Present. So, molar solubility of I cazt ion when caloH) dissociate

in And cache (0. 2m) solution molar Solubility of = 6.2+5) m ot as CaLOH)2 = cat taot - (0.2+5) (25) dow we know that holay solubility 's' of CALOH)2 in o.2M Cache solution or ksp of Calolt) in 0. 2M cacer solution = [cat] [ou]² = (0.2+3) (25)2 =(0.2+5) xus? 0.852+ 453 Hence expression to calculate the molar Solubility is' of Calot) in a 0. 2M Cache solution is equal to 10.852 + 453. Answer - 10.85²+us3