Question

to 0.50 2 1007 . Using the standard Normal distribution tbles, what is the area under the standard Normal curve O 01915 0.532 O 0.1498 0.3413 A o outer comamy pnivces an extremely light laptop snd ehey daimesthe ghyte賦onth, manet, weighing gjy 32 o enne ital-ight ,the leto.the ber heen 33 ounces and a standard deviation of 0.7 ounces What proportion of laptops is overweight (Le, weigh more than 32 ounces)? 0.9236 0.7580 0.076 2400 d·uta drg devinon e' 1 on what-H gould be put on the ehomie" The datribution of actual wegres or s-ounce chocolain ban produced by a cetan machine is tormal. with. "-an of·, eurem . bar wrappers so that only 1% or bars are underweight? s. 7.87 ounces 8.33 unces s.Astudy-cond cted to determinu rimecan preot price of,stock based on the Perto4arnings e. The 'espon" variable in study is: the price of the stock either the NASDAQ r the Dow ones Industrial Average the price-to-caings atio 7. The description of the overall panem ors scatterpǐut should indude the orm rength All of the answers are cormet

Answer 1

Solution:-

3) The area under the standard normal curve corresponding to 0.50 < z < 1.00 is 0.1498 .

P(0.50 < z < 1.00) = P(z > 0.50) - P(z > 1.00)

P(0.50 < z < 1.00) = 0.3085 - 0.1587

P(0.50 < z < 1.00) = 0.1498