Question

THa 3 Trial 2 Triall mcess of KHP 4439 idltial buete reachitg Ginal burcte reacirg 25.30 mL 0.00mL 25.30 mL a.o0mL l0-00mL 0-

NAOH
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Suppose a mono basie base (Boh) Reaction of KHP with base 0-8* +H₂O + BOH - Trial-1 man og KHP = 0.44369 Molar manog kHP = 20similarly of Trial-2 mang kHP = 0.4445g mo1 KMP 0.009127mol 0.44453 204.22 g mor! moly KHP = molf base react mol of base = 0.mass of KHP = molx molar mass nol 0.0098326 20422 = 0.5784 g Ig= 1000mg mang Kup = 1578.4 mg

Add a comment
Know the answer?
Add Answer to:
NAOH THa 3 Trial 2 Triall mcess of KHP 4439 idltial buete reachitg Ginal burcte reacirg...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Objective 1: Standardization with KHP Trial 1 Mass of KHP Trial 2 Trial 3 ,5825 9...

    Objective 1: Standardization with KHP Trial 1 Mass of KHP Trial 2 Trial 3 ,5825 9 53539 1.53169 *Moles of KHP: Initial buret reading: 0.00 mL 10.00 Final buret reading: 0.00ML 8 mb 16.5 mL I 10.9 mL *Volume of NaOH solution used: 16.5 mL 8 mL 10.9mL *Molarity of NaOH solution: Show your calculations here: *Average Molarity of NaOH: Percent Range:

  • В. Titration of KHP Trial 1 Trial 2 Trial 3 Trial 4 0.321ps 0.00 mL 20mL...

    В. Titration of KHP Trial 1 Trial 2 Trial 3 Trial 4 0.321ps 0.00 mL 20mL Q302. 0.334 0.00 mL .10 mL v.O mL 0.328 O.00 mL Ke.20 mL 0.20 mL 1. Mass of KHP T-00 mL Initial buret reading 2. 510 5 10 mL Final buret reading 3. mL .20 ml. 4. Volume NaOH used Moles KHP used 5. mol mol mol mol 6. Moles NaOH used mol mol mol mol 7 Molarity of NaOH M. М М 8....

  • help me answer questions 1-5 3943 ss Trial 2 Trials Table 1: Standardization Data 1.4444 Trial 1 4386 A. Determinati...

    help me answer questions 1-5 3943 ss Trial 2 Trials Table 1: Standardization Data 1.4444 Trial 1 4386 A. Determination of th Vinegar is a solution of that an aqueous aceti experiment, you will to OML Mass of KHP Initial burette reading Final burette reading Lont Om 1912 10.2 q mL 9 mL 10.2 1. Set up a clean, 2. Use the autodis 3. As on day 1, a endpoint (a fic T 10.2 Volume of base used p and...

  • Sample 1 .674a Sample 3 0.00 -63619_573989 Sample 2 Mass of KHP taken Initial NaOH buret...

    Sample 1 .674a Sample 3 0.00 -63619_573989 Sample 2 Mass of KHP taken Initial NaOH buret reading c om m e Final NaOH buret reading 33. ML 32.30ml Volume of NaOH used 33 mL 32.3mL Moles of KHP present 003_ moles_003 mole s kup Molarity of NaOH solution 10 M Mean molarity of NaOH solution and average deviation 0 04 M اور * 5% vinesar Sample 2 WHO Analysis of Vinegar Solution (Part 4a) Identification number (or brand) of vinegar...

  • Please help calculate, Concentration of NaOH is 0.1M. Trial 2 Trial 3 Trial 1 C. #502...

    Please help calculate, Concentration of NaOH is 0.1M. Trial 2 Trial 3 Trial 1 C. #502 0.8236g 0.8389g Mass of impure KHP unknown taken (g 0.8167g 0.00mL. 0.00mL 0.00ml. Initial burette reading (mL) 27.52 mL Final burette reading (mL) 27.52 mL 27.87mL 26,72mL Volume of NaOH used (mLO by mass of impure KHP unknown relative average deviation Trial 1 Trial 2 Trial 3 D. #11 0.3602g 0.3636g Mass of unknown acid (g) 0.00ml 0.00mL 10.00mL Initial burette reading (mL) 5.88mL...

  • Standardization Data Trial 1 Trial 2 Trial 3 Volume of 0.500 M KHP 5.00 ml 5.00...

    Standardization Data Trial 1 Trial 2 Trial 3 Volume of 0.500 M KHP 5.00 ml 5.00 ml 5.00 ml Initial burette reading 0.00 ml 13.10 ml 26.60 ml 26.60 ml 13.20 ml Final burette reading 13.10 ml 13.10 ml Volume of base used (final-initial readings) Data Analysis: (work alone on calculations) 39.60 ml 13.00 ml 3. Calculate the molarity of base for each trial. Use dimensional analysis - show all unit conversions (hint: start with mL of KHP solution used)....

  • Observations: Part 1-Standardization of NaOH Ceho Trial 1 Trial 2 Trial 4 Trial 3 Initial mass...

    Observations: Part 1-Standardization of NaOH Ceho Trial 1 Trial 2 Trial 4 Trial 3 Initial mass weighing vial plus KHP と139 16908 427 IS 4 Final mass weighing vial plus KHP is.118 1s.YT 4.47 Mass of KHP Co 498 Moles of KHP used Moles NaOH used 0.00245% 10.00240円 10.00245 (4 SF) 062453 Initial burette reading of NaOH solution to +/-0.01 mL 00 100 0-00 T10 Final burctte rcading of NaOH solution 19.10 1f 03 02 23.00 to +-0.01 mL. Volume...

  • Mass of empty flask (9) Mass of flask + KHP (9) Mass of KHP (g) TRIAL 1 L TRIAL 2 TRIAL 3 94.560g 89.0050 89 7357 9...

    Mass of empty flask (9) Mass of flask + KHP (9) Mass of KHP (g) TRIAL 1 L TRIAL 2 TRIAL 3 94.560g 89.0050 89 7357 94.9109 89.353 : 90.0949 0.250 0.3489 0.3499 0.00171 mol 0.00170.10 0.00171 wol 10.60 mL 0.83 L 60.50mL 10.83 mL 60.50 ML 124-80 with Moles of KHP Initial buret reading (mL) Final buret reading (mL) Volume NaOH solution used (ml) Moles of NaOH used Molarity NaOH Average Molarity of NaOH 0.00171md 0.00170 ud 0.0017 md

  • 2. Calculate the mass of KHP needed to react completely with 15 mL of a 0.10 M NaOH solution. Consider the reaction...

    2. Calculate the mass of KHP needed to react completely with 15 mL of a 0.10 M NaOH solution. Consider the reaction equation to be as shown below, molar mass of KHP is 204.3g/mol 3. Calculate the molarity of a solution of sodium hydroxide if 23.64 mL of this solution is needed to neutralize 0.5632 g of KHP. 4. It is found that 24.68 mL of 0.1165 M NaOH is needed to titrate 0.2931 g of unknown monoprotic acid to...

  • please answer the question on the bottom. Pwerage Trial 0.4436 16.00 Trial 2 mass KHP (9) Trial 3 0.4445 0.4457 volu...

    please answer the question on the bottom. Pwerage Trial 0.4436 16.00 Trial 2 mass KHP (9) Trial 3 0.4445 0.4457 volume base (mL) 9.70 9.30 NaOH Molarity 0.1358 M 0.2244 M 02347 M 0.1983 M Average these values Vinegar Data for % acetic acid vol Vinegar (ml) 5.00 5.00 5.00 volume base (mL) 20.00 15.00 19.60 Acid Molarity 0.793 0.595M 0.777M 0.722M % Acid 4.76% 3.57% 4.67% 4.33% Unknown Data for molarity HX Unknown Number - 36 vol unknown 10.00...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT