Question

The transverse displacement of a stretched string from equilibrium as a function of time and position is given by: y=0.13 cos(9 x + 45t). x and y are in m; t is in s. The wavelength is The period is ..... 0.1 seconds. The wave moves in the positive x direction. The speed of the wave is 1 m. Less than Greater than True 6 m/s. Less than A traveling, wave can be any function of (2*pi*x/lamda-2*pi*t/period). Calculate the various parameters where needed then select the proper answers. Submit Answer You have entered that answer Previous Tries Calculate the average power transmitted by the string. Data: mass of a 169 Incorrect. Tries 3/12 before m long piece of the string is 3.07 kg. Submit AnswerTries 0/12

Answer 1

y = 0.13 cos (5x-44549 =9 ļ 24 = 45 .: w wave length = = 2mm. $ 0.698m. A = 0.698m : less than (6 trime period at T= 21 see = 0:1396 sec . Ta o.14 sec :: greater than I Ş 0.ly see greater than wave moves in ave a direction cing Speed - $ - ante se als * Average power = 1 / 4 W² Aho ushere pas here on the jw = 4T & A = amplitude P = 4 x 160 x ( 27 ) ² + (0-13)² x 5 Watt 1.3.07 = 0.091 watt ye power Ž 0.091 watt