Question

2. Determining the oxidizing capacity of a household cleanser or liquid bleach (a) Record the following data for the titration of a household cleanser (or bleach). Brand name of cleanser or bleach Data Trial 1 Trial 2 Mass of sample Trial 3 O.15 g 015 Volume of NA2S2O3 titrant O,13 g Final buret reading 150 13-7 13 16.2 19.3 lल mL mL mL Initial buret reading mL 15 mL mL Net volume of Na2S2O3 mL . 2 mL 22 mL Calculation of percentage NAOCI Moles of Na2S203 used mol mol mol Moles of NaOCl reacted mol mol mol Mass of NaOCl in sample g g g Percentage by weight NaOCI (g NaOCl/g sample) x 100% % % % Average % (b) If you have titrated a sample of another cleanser or bleach, record your data below. Brand name of cleanser or bleach E EE
The concentration for Na₂S₂O₄

Answer 1

For determination of the Ouidation capacity of unknown Liquid Bleach You have to do standardisation of Na2S₂O3. first. From the standardisation alata calculate Molarity of Naz S203. Since you have not provided the standardisation data, I will use the value of Molarity of Na2S2O3 as XM Trial 1 Reaction Involved Naou + 2 Na 2S2O3 + H+ Nace + Na2S406 + H2O (1) To find moles of Na2S2O₃ Moles - Molarity & volume = xx 1.3 Net volume of Na₂S2O3 molarity calculated from Standardisation of Na2S203) Trial 1 2. 3 M = M2 = M2 xx13 xx 1.2 x v 2.2 - (2) To find moles of Naou reacted See the reaction 2 moles Na2S₂O3 luact with Imole NaOch Trial xx13 " " " IX X XIS Trial 2 xX12 " " 11 LX XX 1.2

Tria 3 xx 2.2 moles of Na2S2O3 react with 1x2x2.2 moles of Naog - (3) Mars of NaOCI a moles of NaOC X Molar mass of Naou (74-44%) Trial Mars - XXXI:3 X 74:40) = 9 Trial 2 = [X 2X2 X 74. Trial 3 = x 2 X 22 X 74.441 = Co 14 To find 7 of Naoce 60 mass of Naoce x mass of bleach 100