Question

Need to show work

16. Let Y-number of broken eggs in a carton. The probability distribution for Y is given in the table below. Note: a carton of eggs contains 12 eggs. Probability | 0.7 1015 0.06 0.05 0.04 (a) Compute the expected value of Y and explain its meaning. Answer: E(Y) 0.58 (b) If 1,000 egg cartons are inspected, what would be the expected number of broken eggs found? Answer: 580 (c) Why is it that u is not equal to (0+1+2+3+4)/5? (4.2.8)

Answer 1

Y- number ofbroken eggs in carton (a) Expected value ofY is, Y* P 0.7 0.15 0.06 0.05 0.04 0 2 3 4 Total 0 0.15 0.12 0.15 0.16 0.58 Therefore, The expected value is 0.58. In other words, on an average the expected number of broken eggs in carton is 0.58 (b) If 1000 egg cartons are inspected then the expectednumber ofbroken eggs are. = N* E(X)= 1000 * 0.58 580 (c) μ is not equal to (0 + 1 + 2 + 3 + 4)/ 5-10/5-2. Because the unequal probability P(Y) ofrandom variable (Y) for each number ofbroken eggs in carton