Question

In order to receive credit for the homework, you must show all steps for doing a chi square test of independence. These steps include: null and alternative hypothesis); critical value; calculations (show work); reject or accept H; results statement using no relationship or a relationship.

Answer 1

Ans:

H₀:There is no relationship between education and place of residence.

H_a:The education and place of residence are related.

Chi square test for independence:

	Observed(fo)
	No college	4 yr	advanced	Total
Urban	15	12	8	35
suburban	8	15	9	32
rural	6	8	7	21
Total	29	35	24	88
	Expected(fe)
	No college	4 yr	advanced	Total
Urban	11.53	13.92	9.55	35
suburban	10.55	12.73	8.73	32
rural	6.92	8.35	5.73	21
Total	29	35	24	88
	Chi square=(fo-fe)^2/fe
	No college	4 yr	advanced	Total
Urban	1.04	0.26	0.25	1.56
suburban	0.61	0.41	0.01	1.03
rural	0.12	0.01	0.28	0.42
Total	1.78	0.69	0.54	3.01

Test statistic:

Chi square=3.01

df=(3-1)*(3-1)=4

critical chi square value=CHIINV(0.05,4)=9.488

p-value=CHIDIST(3.01,4)=0.5569

As,test statistic is less than critical value,we fail to reject the null hypothesis.

There is not sufficient evidence to conclude that e education and place of residence are related.