Question

A researcher conducts an experiment to examine the relationship between the weight gain (wtgn, gm) of chickens, whose diets had been supplemented by different amounts of lysine, and the amount of lysine (gm) ingested. A random sample of 12 chicks was selected for the study. The R output is given below. Call: lm(formula = wtgn ~ lysine, data = lys) Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 12.57 1.18 10.65 8.9e-07 lysine 35.48 6.89 5.15 0.00043 Residual standard error: 1.02 on 10 degrees of freedom Multiple R-squared: 0.726, Adjusted R-squared: 0.699 F-statistic: 26.5 on 1 and 10 DF, p-value: 0.000432 95% CI 95% PI fit lwr upr fit lwr upr 16.8 15.9 17.8 16.8 14.4 19.3 The Fit information shown at the end of the output is for lysine=0.12. From the interval (15.9,17.8), we can conclude that:

Answer 1

# Introduction:

In given situation regression model is fitted for dependant variable weight gain in gram based on independent variable amount of lysine ingested .

Here , Interpretation of confidence interval for predicted response variable based on x=0.12 is expected

# Answer:

(givin that i as %ー(onfidence interval foy Tt_ indicates that with-_J&% df chick 1onfidanu. enis1 is lits rams din between 15 ulun amountー0d lysine-ingested is O-12