Homework Answers
Standard enthalpy of formation is the energy change when one mole of a substance is formed from its constituent elements in pure form under standard conditions. NiSO4 is formed of Ni, S and O which exist in pure elemental forms as Ni(S), S8 (s) and O2 (g). Thus, option c is correct in which these elements in their pure forms are combining to give one mole of product
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Question 16 (1 point) The standard enthalpy of formation of NiSO4(s) at 25 °C is -872.9...
The standard enthalpy of formation of CO(g) is −111 kJ/mol [refer to this equation C(s) +...
The standard enthalpy of formation of CO(g) is −111 kJ/mol [refer to this equation C(s) + 1/2O2(g) ⟶ CO(g)] What is the ΔHorxn of this reaction? (What is the standard enthalpy change of this reaction?) 2C(s) + O2(g) ⟶ 2CO(g) -253 kJ/mol - 222 kJ/mol -97.1 kJ/mol 534 kJ/mol 124.9 kJ/mol -50.5 kJ/mol 5 points QUESTION 2 (assume A, B, C, and D and E are chemicals) Look at these equations A + B à C ΔH° = -9 kJ/mol rxn...
Question (1 point) Calculate the enthalpy of formation of 1 mole SO2(g) from the standard enthalpy...
Question (1 point) Calculate the enthalpy of formation of 1 mole SO2(g) from the standard enthalpy changes of the following reactions: 280,(8) ► 2002 (8)+02 (8) 2S(s) +302(8) ► 250,(8) s(s) +02(8) - S02(8) AH rxn 1 =1+196 kJ AHPrxn2--790 kJ AHx3 ? 2nd attempt Feedback IN See X -198.23
The standard enthalpy of formation of NH_2(g) id -46 KJ mol^-1.The standard enthalpy of formation of...
The standard enthalpy of formation of NH_2(g) id -46 KJ mol^-1.The standard enthalpy of formation of H_2O(g) is -242 KJ middot mol^-1. The enthalpy of reaction is 906 kl. The standard enthalpy of formation of NO(g)is a. -754.5 kJ middot mol^-1 b. -362 kJ middot mol^-1 c. -196.5 kJ middot mol^-1 d. -90.5 k middot J-mol^-1 e. +90.5 kJ middot mol^- 1 f. +182.5 kJ middot mol^-1 g.+317 kJ middot mol^-1 h. +362 kJ middot mol^-1 i. +409 kJ middot...
Using Hess's Law to Calculate a Standard Enthalpy of Formation On the Solution Calorimetry Lab Report...
Using Hess's Law to Calculate a Standard Enthalpy of Formation On the Solution Calorimetry Lab Report Form, vou will be asked to calculate a standard enthalpy of formation for magnesium oxide based on your experimental results. Below is an example of how to do this type of calculation. Calculate the standard enthalpy of formation of gaseous diborane (B2H6) using the following thermochemical equations: 4 B(s) + 3 O2(g)-> 2 B2O3(s) 2 H2(g) + O2(g) > 2 H20(0) B2H6(8) +3 O2(g)...
Question 13 4 pts Which of the following does not have a standard enthalpy of formation...
Question 13 4 pts Which of the following does not have a standard enthalpy of formation equal to zero at 25 °C and 1.0 atm? 0 Ti (s) O S8 (s) O H2 (g) o They all have standard enthalpy of zero O HCl (g)
Enthalpy of Formation Part 1: Part 2: Part 3: A scientist measures the standard enthalpy change...
Enthalpy of Formation
Part 1:
Part 2:
Part 3:
A scientist measures the standard enthalpy change for the following reaction to be 591.0 kJ : 2H2O(1)—>2H2(g) + O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol. A scientist measures the standard enthalpy change for the following reaction to be -2903.4 kJ: 2C2H6(g) + 7 O2(g)—>4CO2(g) + 6 H2O(g) Based on this value and the standard...
Question 2 (1 point) Saved The standard heat of combustion for naphthalene, C10Hg(s), is -5156.8 kJ...
Question 2 (1 point) Saved The standard heat of combustion for naphthalene, C10Hg(s), is -5156.8 kJ mol-1. Use this value and the given standard enthalpies of formation to calculate the standard enthalpy of formation of C1oHg(s) in kJ mol-1 H20() AHOf: H20() -285.9 kJ mol-1; -285.9 kJ mol-1. CO2(g) = -393.5 kJ mol-1 Hint: Hess' law; write the balanced chemical combustion equation and the chemical equation which defines the AHf of C10H8(s).
Write the balanced chemical equation that represents the standard heat of formation of MgCO3(s) at 298...
Write the balanced chemical equation that represents the standard heat of formation of MgCO3(s) at 298 K. Use the pull-down boxes to specify states. Write fractions with a slash, such as 1/2 for one half. If a box is not needed leave it blank. (s)(l)(g) + (s)(l)(g) + (s)(l)(g) arrow (s)(l)(g) (b) The standard enthalpy change for the following reaction is 479 kJ at 298 K. 2 NiO(s)(arrow)2 Ni(s) + O2(g) What is the standard heat of formation of NiO(s)? kJ/mol
5 Determine the standard enthalpy of formation of Fe2O3(s) given the thermochemical equations below. 2Fe(s) +...
5 Determine the standard enthalpy of formation of Fe2O3(s) given the thermochemical equations below. 2Fe(s) + 3/2 O2(g) → Fe2O3(s) AH(Fe2O3) = ? Fe(s) + 3 H2O() Fe(OH)3(s) + 3/2 H2(g) AH° = +160.9 kJ/mol-rxn H2(g) + 1/2O2(g) → H2O(1) A.H° = -285.8 kJ/mol-rxn Fe2O3(s) + 3 H2O(1) ► Fe(OH),(s) A,Hº +288.6 kJ/mol-rxn
Determine the Standard Enthalpy of Formation Question The enthalpy of formation for ammonia (NHs) is -46.19...
Determine the Standard Enthalpy of Formation Question The enthalpy of formation for ammonia (NHs) is -46.19 k.J/mol. What does this mean? Select the correct answer below O 46.19 kJ of energy are released for every mole of ammonia that is formed from its elements in their most stable states under standard conditions. O 46.19 kJ of energy are absorbed for every mole of ammonia that is formed from its elements in their most stable states under standard conditions. O 46.19...
Question (1 point) Calculate the enthalpy of formation of 1 mole SO2(g) from the standard enthalpy changes of the following reactions: 280,(8) ► 2002 (8)+02 (8) 2S(s) +302(8) ► 250,(8) s(s) +02(8) - S02(8) AH rxn 1 =1+196 kJ AHPrxn2--790 kJ AHx3 ? 2nd attempt Feedback IN See X -198.23
The standard enthalpy of formation of NH_2(g) id -46 KJ mol^-1.The standard enthalpy of formation of H_2O(g) is -242 KJ middot mol^-1. The enthalpy of reaction is 906 kl. The standard enthalpy of formation of NO(g)is a. -754.5 kJ middot mol^-1 b. -362 kJ middot mol^-1 c. -196.5 kJ middot mol^-1 d. -90.5 k middot J-mol^-1 e. +90.5 kJ middot mol^- 1 f. +182.5 kJ middot mol^-1 g.+317 kJ middot mol^-1 h. +362 kJ middot mol^-1 i. +409 kJ middot...
Using Hess's Law to Calculate a Standard Enthalpy of Formation On the Solution Calorimetry Lab Report Form, vou will be asked to calculate a standard enthalpy of formation for magnesium oxide based on your experimental results. Below is an example of how to do this type of calculation. Calculate the standard enthalpy of formation of gaseous diborane (B2H6) using the following thermochemical equations: 4 B(s) + 3 O2(g)-> 2 B2O3(s) 2 H2(g) + O2(g) > 2 H20(0) B2H6(8) +3 O2(g)...
Question 13 4 pts Which of the following does not have a standard enthalpy of formation equal to zero at 25 °C and 1.0 atm? 0 Ti (s) O S8 (s) O H2 (g) o They all have standard enthalpy of zero O HCl (g)
Enthalpy of Formation
Part 1:
Part 2:
Part 3:
A scientist measures the standard enthalpy change for the following reaction to be 591.0 kJ : 2H2O(1)—>2H2(g) + O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol. A scientist measures the standard enthalpy change for the following reaction to be -2903.4 kJ: 2C2H6(g) + 7 O2(g)—>4CO2(g) + 6 H2O(g) Based on this value and the standard...
Question 2 (1 point) Saved The standard heat of combustion for naphthalene, C10Hg(s), is -5156.8 kJ mol-1. Use this value and the given standard enthalpies of formation to calculate the standard enthalpy of formation of C1oHg(s) in kJ mol-1 H20() AHOf: H20() -285.9 kJ mol-1; -285.9 kJ mol-1. CO2(g) = -393.5 kJ mol-1 Hint: Hess' law; write the balanced chemical combustion equation and the chemical equation which defines the AHf of C10H8(s).
5 Determine the standard enthalpy of formation of Fe2O3(s) given the thermochemical equations below. 2Fe(s) + 3/2 O2(g) → Fe2O3(s) AH(Fe2O3) = ? Fe(s) + 3 H2O() Fe(OH)3(s) + 3/2 H2(g) AH° = +160.9 kJ/mol-rxn H2(g) + 1/2O2(g) → H2O(1) A.H° = -285.8 kJ/mol-rxn Fe2O3(s) + 3 H2O(1) ► Fe(OH),(s) A,Hº +288.6 kJ/mol-rxn
Determine the Standard Enthalpy of Formation Question The enthalpy of formation for ammonia (NHs) is -46.19 k.J/mol. What does this mean? Select the correct answer below O 46.19 kJ of energy are released for every mole of ammonia that is formed from its elements in their most stable states under standard conditions. O 46.19 kJ of energy are absorbed for every mole of ammonia that is formed from its elements in their most stable states under standard conditions. O 46.19...
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