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Exercise 10.9(Algorithmic)) Consider the following results for independent random samples taken from two populations Sample 1 Sample 2 n1 10 n2 30 x1- 22.8 x2 20.9 $1-2.9 s2 4.8 a. What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down)? C. At 95% confidence, what is the margin of error (to 1 decimal)? d. what is the 95% confidence interval for the difference between the two population means (to 1 decimal)?
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sample 1 sample 2 22.800 2.900 10.000 20.9000 4.8000 30.0000 S1 52 Point estimate =x1-x2 1.900 312 2 S22 2 = (_+n2) degree of freedom v /(ww-1)+ (n2-1) 26.0000 for 95 % CI & 26 df value of t= margin of error E-t*std error lower confidence bound-mean difference-margin of error- Upper confidence bound-mean differnce +margin of error- 2.0560 2.6080 0.708 4.508

a) point estimate =1.9

b)degree of freedom=26

c)margin of error =2.6

d) 95% CI =-0.7 ;4.5

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