Question

Please show the calculations

Catalysts are molecules that can speed up the rate of a reaction and are regenerated, this allows for effective catalysts to be used in very small quantities with respect to the substrate being transformed. This experiment uses copper acetate as a catalyst at about 12% loading with respect to benzoin. Calculate the amount of copper acetate used to convert 0.620 g of benzoin to benzil, if the catalyst loading is 5% : g 12%:

Answer 1

5% : 0.0265 g

12% : 0.0637 g

Explanation

(1) mass benzoin = 0.620 g

moles benzoin = (mass benzoin) / (molar mass benzoin)

moles benzoin = (0.620 g) / (212.244 g/mol)

moles benzoin = 0.00292 mol

moles copper acetate required = (catalyst loading / 100) * (moles benzoin)

moles copper acetate required = (5 / 100) * (0.00292 mol)

moles copper acetate required = 1.46 x 10^-4 mol

mass copper acetate required = (moles copper acetate required) * (molar mass copper acetate)

mass copper acetate required = (1.46 x 10^-4 mol) * (181.634 g/mol)

mass copper acetate required = 0.0265 g

(2)

moles benzoin = 0.00292 mol

moles copper acetate required = (catalyst loading / 100) * (moles benzoin)

moles copper acetate required = (12 / 100) * (0.00292 mol)

moles copper acetate required = 3.5054 x 10^-4 mol

mass copper acetate required = (moles copper acetate required) * (molar mass copper acetate)

mass copper acetate required = (3.5054 x 10^-4 mol) * (181.634 g/mol)

mass copper acetate required = 0.0637 g