1. Precipitation of Ionic Solids 1. 250.0 mL of 0.0062 M AgNO3 and 250.0 mL of...

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science chemistry

Answer 1

Answer #1

Question 1.

[Ag⁺] = 250 mL * 0.0062 M/(250+250) mL = 0.0031 M

[CO₃^2-] = 250 mL * 0.00014 M/(250+250) mL = 0.00007 M

The ionic product (Kip) of Ag2CO3 = [Ag⁺]²*[CO₃^2-] = (0.0031)²*(0.00007) = 6.727*10^-10

Here, Kip (6.727*10^-10) > Ksp (8.1*10^-12)

Hence, the formation of precipitate (Ag2CO3) takes place.

Answer 2

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