Ce4+ Express your answer in condensed form, in order of increasing orbital energy
Ce4+
Express your answer in condensed form, in order of increasing orbital energy
Homework Answers
Filling order of orbital is:
1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p
Number of electron in Ce = 58
Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10
4f2 5s2 5p6 6s2
Since charge on Ce is +4
So, we need to remove 4 electrons
Electrons are always removed from highest number orbital
Removing 2 electron from 6s
Removing 2 electron from 5p
Final electronic configuration is : 1s2 2s2 2p6 3s2 3p6 3d10 4s2
4p6 4d10 4f2 5s2 5p4
Noble gas having lesser electron than Ce and closest to it is Xenon
(Xe)
Number of electron in Xe = 54
electronic configuration of Xe is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6
4d10 4f2 5s2 5p6 6s2
So, electronic configuration of Ce in noble gas form is: [Xe]
5p4
Answer: [Xe] 5p4
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Ce4+
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