Question

4. As you are an intelligent chemist and you've been doing this long enough to understand some fundamental aspects of safety when mixing/cooking chemicals etc., you decide before you begin this process, to place your reactants and the associated glassware under the vacuum hood just to be on the safe side. Based on your chemical equation above, is there a gas emanating from this reaction and if so, what gas is going up into the hood? a. Yes No. (circle one) b. If you circled yes, identify the gas: cal 5. Assuming you begin your experiment by adding 10.0 g of rubidium carbonate to your hydrobromic acid, what is the theoretical yield of every compound found in your balanced chemical equation? Hint: That would include figuring out how much hydrobromic acid was utilized in the reaction. Show all of your work on the back of these pages! 6. What is an easy way to know if the theoretical values for your products is accurate?

I just need help with the question #5-6

Answer 1

The balancad chemial euatian is shouon bolow RbCog +2HBK Feom the above equation Imale d Rbglog needs 2 mdes 4Helo to Comph the eachon gentally avatlable Heh Gomdeinm actd Containte6) HBlo Aomaining 2RbBptCoo+Haa lupes Ca watn is molar mass RaCog 230.q45 8mo Mars & Rbg cog ubd = 10g Neumber moles 4 Rb, cog lyed mas thelomprnd Milaemas4 thelampend Mular mars d Hek- 80.918lmol wright Pealant Dovsity 46% Commercially auailable Heh 48% HBlo acod Mass 149 g/mL Numbeng mdes R Cog und10 0.0433 mdes 230.qusp/mud AS Per eguation ImdleRboca nead 2 mdles HBo o Complet Hhe reaction and produ 2mdy RbB Imde Coo awd Imde Ho. So G.0433 molesa Rbaco3 needed 2x0-043 moly HBP O.0866 mdes 1 moles Hero need0.0866 mdey Number mars o HBo= needed Number mdes HBbxmdloemas HBb 00866 medtesx 80.q18/a41.0068 17 mazs Heb heeded 70068g 1009 HB Sdution Contain 483 4 HB.So Fd 7.00689 HB lo loe heed 10068 x100g -I4.59 15g 48 g Howeva HBP48). uton Bascd upon the calulations T.o0689 HBb was uttliza mhe above eadtion

Baged upon chemical eguatkon 1 mdlu a Rbgcog Puodubs 2mdsaRbeo and Imdus Cos and Hoo so Thesetical Yield Theoretical Lietd d cog 0.0493 moes RbBb- 0.483 vmdle x 2= C 0866 mdy 4 Theoutical icld H00.0433 mous molar mas RbBh 165.812-9/mal mars Compond Neumberg mdes x mdoemas mdlar mars Coo44.olg/md molar mas Hoo 18015 9/md /4.22129 Theotetical icld RbBpin grams 0.0866 vakX165 919%mt Theoetial Yield = 1.90569 coo imgramd 0 0433 wex 44o8 Theoiutial Hoo m geams o0433 mee x 1801gm 078 9 Licld Cule can find whether Theditial values tuer Pioducts are Collect udt Comuert hom into numaer moe by dividing xidd values in grams by mdlar masshe Peodudts.Then wehave to compare the balaned chemical eguation. How mamy moes readat Peoduad fiow cafon this Stoichiometuic eguation Then at Pesint fhaw many moes Reactants are csed aud fouwanymdes pioduc fias to be Podulad And Hen Compare tis moles erPh Theaetical xicld ncmberg moles I both are same by Theotetial xields Peoducts in gams mdus many 4 Peoduct Basd Theoretical lalue re acasat The metthed
easy way to know the accuracy of the products theoretical values compare this theoretical values with the balanced chemical equation products values. If both are the same then they are accurate. In question number 5 follwed the same method.