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Two hundred thirty employee travel expense reimbursement vouchers were filed last year in the finance department at Ramjac Co

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Answer #1

a) Yes

The probability that a randomly selected sample contains error = 0.0957

X ~ Binomial(n = 7, p = 0.0957)

The probability mass function of X is

P(X = 1) = *0.0957 * (1 – 0.0957)-1, 1 = 0,1,2, ..., 7

b) The probability that the sample contains no erroneous vouchers

P(X =0) = * 0.0957°* (1 – 0.0957)7-0 = 0.4947075 0.4947

c) The probability that the sample contains at least two erroneous vouchers

P(x > 2) = 1 - P(x < 2) = 1 - P(x < 1) = 1 – 0.8609813 = 0.1390187 0.139

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