Question

The amazing Gambini walks across a 30.0-m-long tightrope high above a 3-ring circus. a) If the 75.0-kg Gambini pushes the tightrope down 15.0 cm in the center, find the tension in the tightrope. b) Ifa 10-cm2 area of Gambini's foot presses on the rope, how much pressure does Gambini apply on this area? A-13:

Answer 1

Force balance in vertical Direction (T cos That + T cos That) = 75 times 9.8 2T cos Theta = 735 cos Theta = 15 times 10^- 2/15 cos Theta = 10 - 2 2T times 10^- 2 = 785 T = 36750 N Pressure = Force/Area Force = 75 times 9 .8 = 735 N Pressure = 735/10 times 10^- 4 P = 735000 N/m^2 Ans