Question

Constants A 9.00 m uniform beam is hinged to a vertical wall and held horizontally by a 5.00 m cable attached to the wall 4.00 m above the hinge, as shown in the figure below (Figure 1). The metal of this cable has a test strength of 1.10 kN , which means that it will break if the tension in it exceeds that amount. Part A What is the heaviest beam that the cable can support with the given configuration? You may want to review (Pages 343 - 347). m = 59.9 kg Figure < 1 of 1 > Submit Previous Answers 5.0 m cable 4.0 m All attempts used; correct answer displayed IDENTIFY: The beam is at rest so the forces and torques on it must each balance. SET UP: ET = 0, EFx = 0, EF, = 0. The distance along the beam from the hinge to where the cable is 4.00 m attached is 3.0 m. The angle º that the cable makes with the beam is given by sin = :00 0 = 53.1°. The center of gravity of the beam is 4.5 m from the hinge. Use coordinates with ty upward and +x to the right. Take the pivot at the hinge and let counterclockwise torque be positive. Express the hinge force as components Hy and Hh. Assume H, is downward and that Hh is to the right. If one of these components is actually in the opposite direction we will get a negative value for it. Set the tension in the cable equal to its maximum possible value, T = 1.10 kN. 5.00 m, so
Please help me with both parts b and c. I am confused

Answer 1

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