A uniform E-field (in N/C) is given by -6i + 2j + 3k. A rectangular box is at rest on the origin of the axis system such that one of its faces has an area of 2.0 m^2 in the y/z plane. What is the magnitude of the electric flux ( in Nm^2/C) through the face? Refer to the situation above, what is the total flux ( in NM^2/C) for the entire rectangular surface of the box?
A uniform E-field (in N/C) is given by -6i + 2j + 3k. A rectangular box...
A uniform electric field of magnitude E = 445 N/C makes an angle of theta = 67.0^degree with a plane surface of area A = 3.80 m^2 as in the figure below. Find the electric flux through this surface. N m^2/C
A
uniform electric field of magnitude E = 465 N/C makes an angle of θ
= 61.5° with a plane surface of area A = 3.55 m2 as in the figure
below. Find the electric flux through this surface.
A uniform electric field of magnitude E = 430 N/C makes an angle of θ = 60.5° with a plane surface of area A = 3.65 m2 as in the figure below. Find the electric flux through this surface.
V76 3k and S be the rectangular region with the orientation shown below. Let +6 (0,0,4) (2,0,4) (0,2,0) (2, 2,0) Find a normal vector to the plane (in the upward direction). -8j 4k n V 80 Find the area vector. (0, — 8, — 4) | х A (2 5 -(2 5 2 2 Flux = 5 6j and S be a disk of radius 4 on the plane z = 10 - x - y oriented away from the...
A uniform electric field of magnitude 3.50x104 N/C makes an angle of 47 ° with a plane surface of area 1.63x10-2 m2 What is the electric flux through this surface? N m2/C Submit Request Ans
6. The electric field in the region of space shown is given by E (8i+2yj) N/C where y is in m. What is the magnitude of the electric flux through the top face of the cube shown? 2n 7. a a Charge of uniform linear density (4.0 nC/m) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y-2.5 m.
Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.06 x 104 N/C as shown in the figure below. 30.0 cm 60.0 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. O kNm2/C O (b) Calculate the electric flux through the slanted surface of the box. kNm2/C (c) Calculate the electric flux through the entire surface of the box. kNm2/C Need Help? Read It Watch It
A uniform electric field of magnitude E = 235 N/C makes an angle θ = 45.0o with the normal to the surface and the surface area is 5.50 x 10^4 cm^2 . Find the electric flux through the surface.
A uniform electric field of magnitude 2.30×104 N/C makes an angle of 37 ∘ with a plane surface of area 1.60×10−2 m2 . What is the electric flux through this surface? I tried using this equation but it was wrong: (2.30x10^4)(1.60x10^-2)sin(37)= -236.82 Thank you for the help in advance
A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface (a) What type of charge distribution is inside the surface? C a positive line charge situated on and parallel to the axis of the cylinder O a negatively charged plane parallel to the end faces of the cylinder C a positively charged plane parallel to the end faces of the cylinder a collection of negative point charges arranged in a line at the center...