Question

What is the percent yield if 100. g of C3H8 combusts to produce 200. g CO2? You should write a balanced chemical equation before solving this problem. 75% 66.7% 100% 50%

Answer 1

6 combustion of the C3H8 gives CO2. het see the chemical equation of this reaction. - C3H2 + O₂ CO₂ + H₂O Now, let's balance this equation, - Reactant side c = 3 H = 8 0 = 2 Product Side c = 1 H= 2 0 - 3 Now ist balance no. of hain reactant and product. c=1x3 =3 c=3 C3H8 Now balance 3002 H H = 2*4 = 8 H = 8 O2 = 3002 + 4H₂O Now , let'see for the C3H8 = 3 CO2 Reachant O2 = 3cO₂ + 4H2O < Product Total 'o'. Reactant Product O = 10 0=2 0=2x5=10 :. 100₂ = 3002+440

Now, balance equation 95, 1ca88 +100, 300, + 4 H20 Now let's talk about to yield. Before that we have to calculate theoretical field. There is one simple way to calculate theoretical yield, see, 1 C3Hg = 300, = 3xC + 6x0=(3x1276X16) 449m 1329m ...... Just calculate molecular mass 100 gm = ? ... As in given question ask about 100 gm G Hg so, theoretical yield = 132 9m x 100gm 44 gm theoretical field = 300gm Now Percent yield = Actual yield x too Theoretical yield 200 x 100 ... As in question 300 given 2009m of ces produced 1. Percent yield = 66.6666667 ² 66.67% So the and option 66.671. is correct answer.