Question

Watashi no namae Homework 1 A wooden pallet (20 kg) carrying a load of 600 kg rests on a wooden floor (s 0.2, Pk 0 pallet itself is rated for a maximum load of 2086 kg. 1. How much force must the pallet apply to the load to keep from collapsing? 2. How much force must the floor be able to muster to not collapse? 3. A forklift river decides to push the loaded pallet without lifting it. What force must be applied to just get the pallet moving? Once the pallet starts moving, the driver pushes with the same force as it took to get the pallet moving. How fast is the pallet moving after sliding under the same force you calculated in part 3 after half a second? 4. 5. If the forklift stops pushing, how far does the pallet slide before coming to a stop?

Answer 1

Force by pallet on load in N N = mg rightdoublearrow N = 600 times 9.8 N = 5880 2) Force by Floor is N' = m'g + N = (m' + m)g N' = (600 + 20) 9.8 N = 5880 2) Force by Floor is N' = m'g + N = (m' + m)g N' = (600 + 20)9.8 rightdoublearrow N' = 6076 3) To move pallet force is F = f u_3 N' F = 0.2 times 6076 rightdoublearrow F = 1215.2 N 4) Once it starts moving F = f_k = (m + m') a 1215.2 - 0.17 times 6076 = 620 a a = 0.29 u m.r^2 By v = n + at rightdoublearrow v = 0.294 times 1/2 v = 0.147 m/r 5) By v^2 - u^2 + 2 rightdoublearrow 0.147 2/2 times 0.29 u = d d = 0.0367 m