Question

198 4. A hydrate of zinc sulfate, ZnSO4 XH20, decomposes to produce 43.9 % water. Calculate the water of crystallization (X), and write the formula for the hydrate. Imol Hao 2.44mol H20 0aల Znsou x Lmol Znsoy TO1.45,2n so4 1 2n x 5.a0 65.30 16au v 9e,07 96.07 R1.459 100-43.9= 50. 10 43.99H20 x 50. I 0.35 moLZnSO4 2.44 moLH2D 0.35 moL 2n604.971 Formula of hydrate ZaSO47 H,O Water of crystallization 5. A hydrate of calcium sulfate, CaSO4-XH20, contains 20.9% water. Calculate the water of crystallization (X), and write the formula of the hydrate. I Cax 40.08 I SO4K .07 136.15 mel 100-20.9 79.1 Imol Hzo T8.02g 420 Imol Casou 130.159 easay 1.lo mal Hz0 20.a9 Haox 79.19 Caso x 0.581 moL Ca So4 1.ILo moL Hz0 O.S81 moL CaSo41.9902.00 Formula of hydrate CaSo4 2 H0 Water of crystallization 2 6. (optional) Plaster of Paris, CaSO4 XH20, is a fractional hydrate; that is, one water molecule attaches to more than one formula unit. If a 2.002-g sample has a mass of 1.878 g after heating, find the water of crystallization (X), and write the formula for Plaster of Paris. Ca 40,08 804 96.07 0.124 136. I59 mol Formula of hydrate CaSO4 H20 Water of crystallization Analysis of Alum
am I doing thos correctly? can you help me with the last question and correct me if i am wrong with the other 2? thank you!

Answer 1

Comment in case of any doubt.

Your 4th and 5th answers are correct. 6th one answer is below: mass of Ho in 2.002g sample=(2002 -1.878) = 0.1244 moles of H₂O = 0.1249 789 j = 0.00689 mol - 0.0138 136.159 moles of Casou = 1.8789 gway 136. = 0.0138 me x= miles de = 0.0689 = 20.5 Thus, water of Crystallization is [0.5] and formule - of hydrate is [Casoy, 0.5 H20] 0.038