What is the minimum [I−] that must be added to a 1.0×10−3M solution of Pb2+ in order to form a precipitate of PbI2(s)? The Ksp of PbI2(s) is 8.5×10−9. Report your answer with two significant figures.
PbI2(s) <-> Pb2+(aq) + 2I-(aq)
Ksp = [Pb2+][I-]^2
8.5*10^-9 = (1.0*10^-3)*[I-]^2
[I-]^2 = 8.5*10^-6
[I-] = 2.9*10^-3 M
Answer: 2.9*10^-3 M
What is the minimum [I−] that must be added to a 1.0×10−3M solution of Pb2+ in...
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