3. Determine the pH of a solution upon dissolution of 0.100 M NaCN (pKa = 9.21)....

Question

Question

3. Determine the pH of a solution upon dissolution of 0.100 M NaCN (pKa = 9.21).

(a) 7.82 (b) 2.90 (c) 11.1 (d) 7.00 (e) 13.2

science chemistry

Answer 1

Answer #1

The answer is option C.11.1

Ph = Pka + log ( [A^- ] \ [HA])

Where [A^-] is the concentration of the acid

And the [HA] is the concentration of its conjugate after dissolition

On substituting the values we got 11.1

Answer 2

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