... MIV PRVI ayurvus bulon wat is 0.011 MHCN (K. 3.5 x 10 )? 22. What...

Question

Question

science chemistry

Answer 1

Answer #1

22)

Ka = 3.5*10^-4

pKa = - log (Ka)

= - log(3.5*10^-4)

= 3.456

use:

pH = pKa + log {[conjugate base]/[acid]}

pH = pKa + log {[CN-]/[HCN]}

= 3.456+ log {1.5*10^-2/1.1*10^-2}

= 3.591

Answer: 3.59

Answer 2

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