Solution:
Here, we have to use z test for the population proportion.
Null hypothesis: H0: The percentage of people who believe on lunar landing of Apollo is 28%.
Alternative hypothesis: Ha: The percentage of people who believe on lunar landing of Apollo is not 28%.
H0: p = 0.28 versus Ha: p ≠ 0.28
This is a two tailed test.
We assume level of significance = α = 0.05
We are given
x = number of items of interest = 25
n = sample size = 75
We are given n = 75, this means sample size is adequate to use z or normal distribution.
np = 75*0.28 = 21
nq = 75*0.72 = 54
np & nq > 5, so we can use normal approximation.
Test statistic formula for this test is given as below:
Z = (p̂ - p)/sqrt(pq/n)
Where, p̂ = Sample proportion, p is population proportion, q = 1 - p, and n is sample size
p̂ = x/n = 25/75 = 0.333333333
p = 0.28
q = 1 - p = 0.72
Z = (p̂ - p)/sqrt(pq/n)
Z = (0.333333333 – 0.28)/sqrt(0.28*0.72/75)
Z = 1.0287
P-value = 0.3036
(by using z-table or excel)
P-value > α = 0.05
So, we do not reject the null hypothesis
There is sufficient evidence to conclude that the the percentage of people who believe on lunar landing of Apollo is 28%.
We conclude that the percentage is the same as its 1969 value.
Shortly after the Apollo 11 lunar landing on July 20, 1969 a survey revealed that 28%...
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