to solve it we have to refer
standard reduction potential table . according to that , the
reduction potential are positive for the elements/ions below the
hydrogen, and negative for the elements which are above to it .
such that the elements lye above the are good reducing agent and
get oxidised at Anode. and reduce hydrogen gas.
for known reduction potentials, cell potential is determined
as-
E(cell) = E ( cathode) - E (anode)
if we know oxidation potential of any half cell then by
reverting the sign ( + to - and vice versa ) we get Reduction
potential.
in attachment Column A represent Oxidation
potentials
while Column B represent Reduction potential of
electrodes.
- Copper and silver : Reduction potential for Silver is more positive then copper reence copper Reduces Copper oxidized and silver Reduled (Anode) Cu (S) cut2 I 4at te Agts) (Cathode) - Ecell = Ecathode de Call Roection & Aging - Ecuyaute menores Cull) +243* -uttag Cu (s) + 2Ag Ecell = 0.80 -0.34 = 0.46 volt 1. Copper and line E celu = Et fcu - E24/2n+2 ty Zn (s) + Cut? → Zuth + Gulsy" f ele = 01347- (-0.76) = h'l voer - Ca - IRON and copper: Fell Efene - E 1/2472 M? Eull = -0.44-(-0.76) -0,32 volt Bromine and zine: E cell = € Byg/Br - kan/znt2 TE 1 Cell =1.06-(-0.76) = 1.82 voer Iodine and chlorine: locine is at Anode 1 , Ecell = Elice - 15 Ewe = 1:36 -0.54 = 0.82 voerd Copper And Chlorine - ine - Anode is Copper Hence oxidan'm A fer copper A Fall = Edice - Eutycu Eall 2 1:36 - 0:34 102 volt cell 1 Column A Column B (Reduction potential) Cu & Ag T -0134 +0.80 Cu & Zn +0.76 + 0134 (column A fe & cu +0.44 +0134 Represent Br & Zn 1, 40176 +1:06 Oxidaho Iz I a -0.54 +1:36 Potential ) cu & ch / -0.34 +1:36 1